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6x^2-142x+700=0
a = 6; b = -142; c = +700;
Δ = b2-4ac
Δ = -1422-4·6·700
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-142)-58}{2*6}=\frac{84}{12} =7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-142)+58}{2*6}=\frac{200}{12} =16+2/3 $
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